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130034344033 = 1152164735069
BaseRepresentation
bin111100100011010100…
…1101010000001100001
3110102122022120002210001
41321012221222001201
54112302243002113
6135423103140001
712252241454506
oct1710651520141
9412568502701
10130034344033
1150168aa7330
12212502a4601
13c35403ab49
146417c894ad
1535b0d997dd
hex1e46a6a061

130034344033 has 16 divisors (see below), whose sum is σ = 142351655040. Its totient is φ = 117800425600.

The previous prime is 130034344021. The next prime is 130034344039. The reversal of 130034344033 is 330443430031.

It is a happy number.

It is a de Polignac number, because none of the positive numbers 2k-130034344033 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 130034343992 and 130034344010.

It is not an unprimeable number, because it can be changed into a prime (130034344039) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 3690423 + ... + 3725491.

It is an arithmetic number, because the mean of its divisors is an integer number (8896978440).

Almost surely, 2130034344033 is an apocalyptic number.

It is an amenable number.

130034344033 is a deficient number, since it is larger than the sum of its proper divisors (12317311007).

130034344033 is a wasteful number, since it uses less digits than its factorization.

130034344033 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 36248.

The product of its (nonzero) digits is 15552, while the sum is 28.

Adding to 130034344033 its reverse (330443430031), we get a palindrome (460477774064).

The spelling of 130034344033 in words is "one hundred thirty billion, thirty-four million, three hundred forty-four thousand, thirty-three".

Divisors: 1 11 521 647 5731 7117 35069 337087 385759 3707957 18270949 22689643 200980439 249586073 11821304003 130034344033