130034344021 has 2 divisors, whose sum is σ = 130034344022. Its totient is φ = 130034344020.

The previous prime is 130034344019. The next prime is 130034344039. The reversal of 130034344021 is 120443430031.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 126139335921 + 3895008100 = 355161^2 + 62410^2 .

It is a cyclic number.

It is not a de Polignac number, because 130034344021 - 2¹ = 130034344019 is a prime.

Together with 130034344019, it forms a pair of twin primes.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (130034344081) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65017172010 + 65017172011.

It is an arithmetic number, because the mean of its divisors is an integer number (65017172011).

Almost surely, 2^130034344021 is an apocalyptic number.

It is an amenable number.

130034344021 is a deficient number, since it is larger than the sum of its proper divisors (1).

130034344021 is an equidigital number, since it uses as much as digits as its factorization.

130034344021 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 3456, while the sum is 25.

Adding to 130034344021 its reverse (120443430031), we get a palindrome (250477774052).

The spelling of 130034344021 in words is "one hundred thirty billion, thirty-four million, three hundred forty-four thousand, twenty-one".