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130034523221353 is a prime number
BaseRepresentation
bin11101100100010000000101…
…100100001010110101101001
3122001102011211111112122100201
4131210100011210022311221
5114020441200421040403
61140321011342232201
736250453464224542
oct3544200544126551
9561364744478321
10130034523221353
1138484371402423
121270168a885661
135773283a9450a
1424179c12394c9
15100776a34b21d
hex76440590ad69

130034523221353 has 2 divisors, whose sum is σ = 130034523221354. Its totient is φ = 130034523221352.

The previous prime is 130034523221279. The next prime is 130034523221423. The reversal of 130034523221353 is 353122325430031.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 127821950270569 + 2212572950784 = 11305837^2 + 1487472^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-130034523221353 is a prime.

It is not a weakly prime, because it can be changed into another prime (130034523221453) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65017261610676 + 65017261610677.

It is an arithmetic number, because the mean of its divisors is an integer number (65017261610677).

Almost surely, 2130034523221353 is an apocalyptic number.

It is an amenable number.

130034523221353 is a deficient number, since it is larger than the sum of its proper divisors (1).

130034523221353 is an equidigital number, since it uses as much as digits as its factorization.

130034523221353 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 194400, while the sum is 37.

Adding to 130034523221353 its reverse (353122325430031), we get a palindrome (483156848651384).

The spelling of 130034523221353 in words is "one hundred thirty trillion, thirty-four billion, five hundred twenty-three million, two hundred twenty-one thousand, three hundred fifty-three".