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1300355083 is a prime number
BaseRepresentation
bin100110110000001…
…1101100000001011
310100121211212211101
41031200131200023
510130342330313
6333011042231
744136556456
oct11540354013
93317755741
101300355083
11608020025
123035a0377
131795307a1
14c49b449d
15792605dd
hex4d81d80b

1300355083 has 2 divisors, whose sum is σ = 1300355084. Its totient is φ = 1300355082.

The previous prime is 1300354981. The next prime is 1300355101. The reversal of 1300355083 is 3805530031.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 1300355083 - 29 = 1300354571 is a prime.

It is not a weakly prime, because it can be changed into another prime (1300355183) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 650177541 + 650177542.

It is an arithmetic number, because the mean of its divisors is an integer number (650177542).

Almost surely, 21300355083 is an apocalyptic number.

1300355083 is a deficient number, since it is larger than the sum of its proper divisors (1).

1300355083 is an equidigital number, since it uses as much as digits as its factorization.

1300355083 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 5400, while the sum is 28.

The square root of 1300355083 is about 36060.4365336861. The cubic root of 1300355083 is about 1091.4922419792.

It can be divided in two parts, 13003 and 55083, that added together give a palindrome (68086).

The spelling of 1300355083 in words is "one billion, three hundred million, three hundred fifty-five thousand, eighty-three".