Base | Representation |
---|---|
bin | 11000001110001100… |
… | …10100111111100011 |
3 | 1020120021022201010222 |
4 | 30013012110333203 |
5 | 203113011020001 |
6 | 5550212513255 |
7 | 640152121043 |
oct | 140706247743 |
9 | 36507281128 |
10 | 13004001251 |
11 | 557346867a |
12 | 262b01b82b |
13 | 12c3172cc7 |
14 | 8b50cb723 |
15 | 51199261b |
hex | 307194fe3 |
13004001251 has 2 divisors, whose sum is σ = 13004001252. Its totient is φ = 13004001250.
The previous prime is 13004001239. The next prime is 13004001319. The reversal of 13004001251 is 15210040031.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 13004001251 - 210 = 13004000227 is a prime.
It is not a weakly prime, because it can be changed into another prime (13004001851) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6502000625 + 6502000626.
It is an arithmetic number, because the mean of its divisors is an integer number (6502000626).
Almost surely, 213004001251 is an apocalyptic number.
13004001251 is a deficient number, since it is larger than the sum of its proper divisors (1).
13004001251 is an equidigital number, since it uses as much as digits as its factorization.
13004001251 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 120, while the sum is 17.
Adding to 13004001251 its reverse (15210040031), we get a palindrome (28214041282).
The spelling of 13004001251 in words is "thirteen billion, four million, one thousand, two hundred fifty-one".
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