Base | Representation |
---|---|
bin | 11101100100010101001111… |
… | …000011000110110011001100 |
3 | 122001102201002202002200121002 |
4 | 131210111033003012303030 |
5 | 114021034011031112330 |
6 | 1140323324050355432 |
7 | 36251040455661365 |
oct | 3544251703066314 |
9 | 561381082080532 |
10 | 130040051035340 |
11 | 38486748743936 |
12 | 12702771b8bb78 |
13 | 5773955096174 |
14 | 2417d87452b6c |
15 | 10079907b1e45 |
hex | 76454f0c6ccc |
130040051035340 has 72 divisors (see below), whose sum is σ = 281198691417168. Its totient is φ = 50512664737920.
The previous prime is 130040051035253. The next prime is 130040051035357. The reversal of 130040051035340 is 43530150040031.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 3765746 + ... + 16560825.
It is an arithmetic number, because the mean of its divisors is an integer number (3905537380794).
Almost surely, 2130040051035340 is an apocalyptic number.
130040051035340 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
130040051035340 is an abundant number, since it is smaller than the sum of its proper divisors (151158640381828).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
130040051035340 is a wasteful number, since it uses less digits than its factorization.
130040051035340 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 20326839 (or 20326794 counting only the distinct ones).
The product of its (nonzero) digits is 10800, while the sum is 29.
The spelling of 130040051035340 in words is "one hundred thirty trillion, forty billion, fifty-one million, thirty-five thousand, three hundred forty".
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