Base | Representation |
---|---|
bin | 111100100011011111… |
… | …1100111010011001010 |
3 | 110102122201101112112120 |
4 | 1321012333213103022 |
5 | 4112310231200132 |
6 | 135423430352110 |
7 | 12252341420046 |
oct | 1710677472312 |
9 | 412581345476 |
10 | 130040100042 |
11 | 50171278966 |
12 | 212521bb636 |
13 | c3552a4a78 |
14 | 6418947026 |
15 | 35b163502c |
hex | 1e46fe74ca |
130040100042 has 16 divisors (see below), whose sum is σ = 260102858400. Its totient is φ = 43342923632.
The previous prime is 130040100023. The next prime is 130040100077. The reversal of 130040100042 is 240001040031.
It is a junction number, because it is equal to n+sod(n) for n = 130040099994 and 130040100030.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 869028 + ... + 1007615.
It is an arithmetic number, because the mean of its divisors is an integer number (16256428650).
Almost surely, 2130040100042 is an apocalyptic number.
130040100042 is an abundant number, since it is smaller than the sum of its proper divisors (130062758358).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
130040100042 is a wasteful number, since it uses less digits than its factorization.
130040100042 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1888197.
The product of its (nonzero) digits is 96, while the sum is 15.
Adding to 130040100042 its reverse (240001040031), we get a palindrome (370041140073).
The spelling of 130040100042 in words is "one hundred thirty billion, forty million, one hundred thousand, forty-two".
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