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130040219 is a prime number
BaseRepresentation
bin1111100000001…
…00000110011011
3100001200201122102
413300010012123
5231242241334
620523114015
73136216001
oct760040633
9301621572
10130040219
116744a161
123767290b
1320c30b9a
14133b0a71
15b63a67e
hex7c0419b

130040219 has 2 divisors, whose sum is σ = 130040220. Its totient is φ = 130040218.

The previous prime is 130040179. The next prime is 130040243. The reversal of 130040219 is 912040031.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 130040219 - 216 = 129974683 is a prime.

It is a super-2 number, since 2×1300402192 = 33820917115135922, which contains 22 as substring.

It is a Chen prime.

It is a self number, because there is not a number n which added to its sum of digits gives 130040219.

It is not a weakly prime, because it can be changed into another prime (130040269) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65020109 + 65020110.

It is an arithmetic number, because the mean of its divisors is an integer number (65020110).

Almost surely, 2130040219 is an apocalyptic number.

130040219 is a deficient number, since it is larger than the sum of its proper divisors (1).

130040219 is an equidigital number, since it uses as much as digits as its factorization.

130040219 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 216, while the sum is 20.

The square root of 130040219 is about 11403.5178344228. The cubic root of 130040219 is about 506.6319378801.

The spelling of 130040219 in words is "one hundred thirty million, forty thousand, two hundred nineteen".