Base | Representation |
---|---|
bin | 11101100100010101100101… |
… | …001010101111001000101000 |
3 | 122001102202001121101110200110 |
4 | 131210111211022233020220 |
5 | 114021040241031244222 |
6 | 1140323424544334320 |
7 | 36251052613162524 |
oct | 3544254512571050 |
9 | 561382047343613 |
10 | 130040422134312 |
11 | 38486919169aa8 |
12 | 127028563143a0 |
13 | 57739b3c28a61 |
14 | 2417dc0852d84 |
15 | 10079b316730c |
hex | 7645652af228 |
130040422134312 has 512 divisors, whose sum is σ = 371204049162240. Its totient is φ = 37736202240000.
The previous prime is 130040422134277. The next prime is 130040422134317. The reversal of 130040422134312 is 213431224040031.
It is a super-2 number, since 2×1300404221343122 (a number of 29 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 130040422134312.
It is not an unprimeable number, because it can be changed into a prime (130040422134317) by changing a digit.
It is a polite number, since it can be written in 127 ways as a sum of consecutive naturals, for example, 25148019487 + ... + 25148024657.
It is an arithmetic number, because the mean of its divisors is an integer number (725007908520).
Almost surely, 2130040422134312 is an apocalyptic number.
130040422134312 is a gapful number since it is divisible by the number (12) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 130040422134312, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (185602024581120).
130040422134312 is an abundant number, since it is smaller than the sum of its proper divisors (241163627027928).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
130040422134312 is a wasteful number, since it uses less digits than its factorization.
130040422134312 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 5825 (or 5821 counting only the distinct ones).
The product of its (nonzero) digits is 13824, while the sum is 30.
Adding to 130040422134312 its reverse (213431224040031), we get a palindrome (343471646174343).
The spelling of 130040422134312 in words is "one hundred thirty trillion, forty billion, four hundred twenty-two million, one hundred thirty-four thousand, three hundred twelve".
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