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130040422134312 = 2331723411634015171
BaseRepresentation
bin11101100100010101100101…
…001010101111001000101000
3122001102202001121101110200110
4131210111211022233020220
5114021040241031244222
61140323424544334320
736251052613162524
oct3544254512571050
9561382047343613
10130040422134312
1138486919169aa8
12127028563143a0
1357739b3c28a61
142417dc0852d84
1510079b316730c
hex7645652af228

130040422134312 has 512 divisors, whose sum is σ = 371204049162240. Its totient is φ = 37736202240000.

The previous prime is 130040422134277. The next prime is 130040422134317. The reversal of 130040422134312 is 213431224040031.

It is a super-2 number, since 2×1300404221343122 (a number of 29 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 130040422134312.

It is not an unprimeable number, because it can be changed into a prime (130040422134317) by changing a digit.

It is a polite number, since it can be written in 127 ways as a sum of consecutive naturals, for example, 25148019487 + ... + 25148024657.

It is an arithmetic number, because the mean of its divisors is an integer number (725007908520).

Almost surely, 2130040422134312 is an apocalyptic number.

130040422134312 is a gapful number since it is divisible by the number (12) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 130040422134312, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (185602024581120).

130040422134312 is an abundant number, since it is smaller than the sum of its proper divisors (241163627027928).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

130040422134312 is a wasteful number, since it uses less digits than its factorization.

130040422134312 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 5825 (or 5821 counting only the distinct ones).

The product of its (nonzero) digits is 13824, while the sum is 30.

Adding to 130040422134312 its reverse (213431224040031), we get a palindrome (343471646174343).

The spelling of 130040422134312 in words is "one hundred thirty trillion, forty billion, four hundred twenty-two million, one hundred thirty-four thousand, three hundred twelve".