Base | Representation |
---|---|
bin | 110001100110… |
… | …110100010011 |
3 | 220110200012112 |
4 | 301212310103 |
5 | 11312112201 |
6 | 1142415535 |
7 | 215350454 |
oct | 61466423 |
9 | 26420175 |
10 | 13004051 |
11 | 7382155 |
12 | 44315ab |
13 | 2904008 |
14 | 1a2712b |
15 | 121d0bb |
hex | c66d13 |
13004051 has 2 divisors, whose sum is σ = 13004052. Its totient is φ = 13004050.
The previous prime is 13003987. The next prime is 13004063. The reversal of 13004051 is 15040031.
13004051 is digitally balanced in base 2 and base 3, because in such bases it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13004051 - 26 = 13003987 is a prime.
It is not a weakly prime, because it can be changed into another prime (13004071) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6502025 + 6502026.
It is an arithmetic number, because the mean of its divisors is an integer number (6502026).
Almost surely, 213004051 is an apocalyptic number.
13004051 is a deficient number, since it is larger than the sum of its proper divisors (1).
13004051 is an equidigital number, since it uses as much as digits as its factorization.
13004051 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 60, while the sum is 14.
The square root of 13004051 is about 3606.1130043303. The cubic root of 13004051 is about 235.1578899710.
Adding to 13004051 its reverse (15040031), we get a palindrome (28044082).
The spelling of 13004051 in words is "thirteen million, four thousand, fifty-one".
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