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130041111343 = 11134179280759
BaseRepresentation
bin111100100011100001…
…1011110001100101111
3110102122210021220210011
41321013003132030233
54112311011030333
6135423504154051
712252353131333
oct1710703361457
9412583256704
10130041111343
11501718a9750
1221252608927
13c35556a180
146418b2b7c3
1535b17849cd
hex1e470de32f

130041111343 has 32 divisors (see below), whose sum is σ = 158483404800. Its totient is φ = 105115795200.

The previous prime is 130041111307. The next prime is 130041111353. The reversal of 130041111343 is 343111140031.

It is not a de Polignac number, because 130041111343 - 29 = 130041110831 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (130041111353) by changing a digit.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 322798 + ... + 603556.

It is an arithmetic number, because the mean of its divisors is an integer number (4952606400).

Almost surely, 2130041111343 is an apocalyptic number.

130041111343 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

130041111343 is a deficient number, since it is larger than the sum of its proper divisors (28442293457).

130041111343 is a wasteful number, since it uses less digits than its factorization.

130041111343 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 280903.

The product of its (nonzero) digits is 432, while the sum is 22.

Adding to 130041111343 its reverse (343111140031), we get a palindrome (473152251374).

The spelling of 130041111343 in words is "one hundred thirty billion, forty-one million, one hundred eleven thousand, three hundred forty-three".

Divisors: 1 11 13 41 79 143 451 533 869 1027 3239 5863 11297 35629 42107 280759 463177 3088349 3649867 11511119 22179961 40148537 126622309 149644547 243979571 288339493 909378401 1646090017 3171734423 10003162411 11821919213 130041111343