Search a number
-
+
13004124230017 is a prime number
BaseRepresentation
bin1011110100111100001000…
…1101001001000110000001
31201001011220202222010021101
42331033002031021012001
53201024421300330032
643354002345054401
72511342215104534
oct275170215110601
951034822863241
1013004124230017
114164022124858
121560352a87401
1373438c2551cb
1432d58da76a1b
1517840179ade7
hexbd3c2349181

13004124230017 has 2 divisors, whose sum is σ = 13004124230018. Its totient is φ = 13004124230016.

The previous prime is 13004124229981. The next prime is 13004124230021. The reversal of 13004124230017 is 71003242140031.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 7432253678656 + 5571870551361 = 2726216^2 + 2360481^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13004124230017 is a prime.

It is not a weakly prime, because it can be changed into another prime (13004124233017) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6502062115008 + 6502062115009.

It is an arithmetic number, because the mean of its divisors is an integer number (6502062115009).

Almost surely, 213004124230017 is an apocalyptic number.

It is an amenable number.

13004124230017 is a deficient number, since it is larger than the sum of its proper divisors (1).

13004124230017 is an equidigital number, since it uses as much as digits as its factorization.

13004124230017 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 4032, while the sum is 28.

Adding to 13004124230017 its reverse (71003242140031), we get a palindrome (84007366370048).

The spelling of 13004124230017 in words is "thirteen trillion, four billion, one hundred twenty-four million, two hundred thirty thousand, seventeen".