Base | Representation |
---|---|
bin | 1011110100111100001000… |
… | …1101001001000110000001 |
3 | 1201001011220202222010021101 |
4 | 2331033002031021012001 |
5 | 3201024421300330032 |
6 | 43354002345054401 |
7 | 2511342215104534 |
oct | 275170215110601 |
9 | 51034822863241 |
10 | 13004124230017 |
11 | 4164022124858 |
12 | 1560352a87401 |
13 | 73438c2551cb |
14 | 32d58da76a1b |
15 | 17840179ade7 |
hex | bd3c2349181 |
13004124230017 has 2 divisors, whose sum is σ = 13004124230018. Its totient is φ = 13004124230016.
The previous prime is 13004124229981. The next prime is 13004124230021. The reversal of 13004124230017 is 71003242140031.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 7432253678656 + 5571870551361 = 2726216^2 + 2360481^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13004124230017 is a prime.
It is not a weakly prime, because it can be changed into another prime (13004124233017) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6502062115008 + 6502062115009.
It is an arithmetic number, because the mean of its divisors is an integer number (6502062115009).
Almost surely, 213004124230017 is an apocalyptic number.
It is an amenable number.
13004124230017 is a deficient number, since it is larger than the sum of its proper divisors (1).
13004124230017 is an equidigital number, since it uses as much as digits as its factorization.
13004124230017 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 4032, while the sum is 28.
Adding to 13004124230017 its reverse (71003242140031), we get a palindrome (84007366370048).
The spelling of 13004124230017 in words is "thirteen trillion, four billion, one hundred twenty-four million, two hundred thirty thousand, seventeen".
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