Base | Representation |
---|---|
bin | 111100100011100001… |
… | …1111110101011110010 |
3 | 110102122210112200022021 |
4 | 1321013003332223302 |
5 | 4112311024310102 |
6 | 135423511102054 |
7 | 12252354224266 |
oct | 1710703765362 |
9 | 412583480267 |
10 | 130041244402 |
11 | 5017198a713 |
12 | 2125267192a |
13 | c3555b58c4 |
14 | 6418b640a6 |
15 | 35b17ae137 |
hex | 1e470feaf2 |
130041244402 has 4 divisors (see below), whose sum is σ = 195061866606. Its totient is φ = 65020622200.
The previous prime is 130041244387. The next prime is 130041244453. The reversal of 130041244402 is 204442140031.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 82346615521 + 47694628881 = 286961^2 + 218391^2 .
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 32510311099 + ... + 32510311102.
Almost surely, 2130041244402 is an apocalyptic number.
130041244402 is a deficient number, since it is larger than the sum of its proper divisors (65020622204).
130041244402 is an equidigital number, since it uses as much as digits as its factorization.
130041244402 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 65020622203.
The product of its (nonzero) digits is 3072, while the sum is 25.
Adding to 130041244402 its reverse (204442140031), we get a palindrome (334483384433).
The spelling of 130041244402 in words is "one hundred thirty billion, forty-one million, two hundred forty-four thousand, four hundred two".
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