Base | Representation |
---|---|
bin | 11101100100010110011011… |
… | …100010000111110011000111 |
3 | 122001102211102011122221122220 |
4 | 131210112123202013303013 |
5 | 114021044123030444221 |
6 | 1140324055250023423 |
7 | 36251114326665303 |
oct | 3544263342076307 |
9 | 561384364587586 |
10 | 130041334234311 |
11 | 38487247006255 |
12 | 12702a6b877b73 |
13 | 5773acab9aab6 |
14 | 2418069a3cd03 |
15 | 1007a182840c6 |
hex | 76459b887cc7 |
130041334234311 has 32 divisors (see below), whose sum is σ = 178215883161600. Its totient is φ = 84313584257760.
The previous prime is 130041334234291. The next prime is 130041334234313. The reversal of 130041334234311 is 113432433140031.
It is not a de Polignac number, because 130041334234311 - 213 = 130041334226119 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (130041334234313) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 242220070 + ... + 242756348.
It is an arithmetic number, because the mean of its divisors is an integer number (5569246348800).
Almost surely, 2130041334234311 is an apocalyptic number.
130041334234311 is a deficient number, since it is larger than the sum of its proper divisors (48174548927289).
130041334234311 is a wasteful number, since it uses less digits than its factorization.
130041334234311 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 551699.
The product of its (nonzero) digits is 31104, while the sum is 33.
Adding to 130041334234311 its reverse (113432433140031), we get a palindrome (243473767374342).
The spelling of 130041334234311 in words is "one hundred thirty trillion, forty-one billion, three hundred thirty-four million, two hundred thirty-four thousand, three hundred eleven".
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