Base | Representation |
---|---|
bin | 10010111011000110101… |
… | …110001110110000101001 |
3 | 11121022121002121111111021 |
4 | 102323012232032300221 |
5 | 132301222004144431 |
6 | 2433222455532441 |
7 | 162644321510161 |
oct | 22730656166051 |
9 | 4538532544437 |
10 | 1300414131241 |
11 | 46155896a115 |
12 | 19004208a121 |
13 | 95822b45b04 |
14 | 46d2458b5a1 |
15 | 23c6047ab11 |
hex | 12ec6b8ec29 |
1300414131241 has 8 divisors (see below), whose sum is σ = 1312438406400. Its totient is φ = 1288398912192.
The previous prime is 1300414131223. The next prime is 1300414131307. The reversal of 1300414131241 is 1421314140031.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1300414131241 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (1300414138241) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1975341 + ... + 2550058.
It is an arithmetic number, because the mean of its divisors is an integer number (164054800800).
Almost surely, 21300414131241 is an apocalyptic number.
It is an amenable number.
1300414131241 is a deficient number, since it is larger than the sum of its proper divisors (12024275159).
1300414131241 is a wasteful number, since it uses less digits than its factorization.
1300414131241 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 4528055.
The product of its (nonzero) digits is 1152, while the sum is 25.
Adding to 1300414131241 its reverse (1421314140031), we get a palindrome (2721728271272).
The spelling of 1300414131241 in words is "one trillion, three hundred billion, four hundred fourteen million, one hundred thirty-one thousand, two hundred forty-one".
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