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1300414131241 = 11325434525399
BaseRepresentation
bin10010111011000110101…
…110001110110000101001
311121022121002121111111021
4102323012232032300221
5132301222004144431
62433222455532441
7162644321510161
oct22730656166051
94538532544437
101300414131241
1146155896a115
1219004208a121
1395822b45b04
1446d2458b5a1
1523c6047ab11
hex12ec6b8ec29

1300414131241 has 8 divisors (see below), whose sum is σ = 1312438406400. Its totient is φ = 1288398912192.

The previous prime is 1300414131223. The next prime is 1300414131307. The reversal of 1300414131241 is 1421314140031.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1300414131241 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1300414138241) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1975341 + ... + 2550058.

It is an arithmetic number, because the mean of its divisors is an integer number (164054800800).

Almost surely, 21300414131241 is an apocalyptic number.

It is an amenable number.

1300414131241 is a deficient number, since it is larger than the sum of its proper divisors (12024275159).

1300414131241 is a wasteful number, since it uses less digits than its factorization.

1300414131241 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4528055.

The product of its (nonzero) digits is 1152, while the sum is 25.

Adding to 1300414131241 its reverse (1421314140031), we get a palindrome (2721728271272).

The spelling of 1300414131241 in words is "one trillion, three hundred billion, four hundred fourteen million, one hundred thirty-one thousand, two hundred forty-one".

Divisors: 1 113 2543 287359 4525399 511370087 11508089657 1300414131241