1300414138241 has 2 divisors, whose sum is σ = 1300414138242. Its totient is φ = 1300414138240.

The previous prime is 1300414138237. The next prime is 1300414138259. The reversal of 1300414138241 is 1428314140031.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1237912138225 + 62502000016 = 1112615^2 + 250004^2 .

It is a cyclic number.

It is not a de Polignac number, because 1300414138241 - 2² = 1300414138237 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1300414138198 and 1300414138207.

It is not a weakly prime, because it can be changed into another prime (1300414138271) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 650207069120 + 650207069121.

It is an arithmetic number, because the mean of its divisors is an integer number (650207069121).

Almost surely, 2^{1300414138241} is an apocalyptic number.

It is an amenable number.

1300414138241 is a deficient number, since it is larger than the sum of its proper divisors (1).

1300414138241 is an equidigital number, since it uses as much as digits as its factorization.

1300414138241 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 9216, while the sum is 32.

Adding to 1300414138241 its reverse (1428314140031), we get a palindrome (2728728278272).

The spelling of 1300414138241 in words is "one trillion, three hundred billion, four hundred fourteen million, one hundred thirty-eight thousand, two hundred forty-one".