13004152531 has 4 divisors (see below), whose sum is σ = 13005711432. Its totient is φ = 13002593632.

The previous prime is 13004152507. The next prime is 13004152541. The reversal of 13004152531 is 13525140031.

It is a happy number.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 13004152531 - 2⁹ = 13004152019 is a prime.

It is a super-2 number, since 2×13004152531² (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13004152496 and 13004152505.

It is not an unprimeable number, because it can be changed into a prime (13004152541) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 766870 + ... + 783643.

It is an arithmetic number, because the mean of its divisors is an integer number (3251427858).

Almost surely, 2^13004152531 is an apocalyptic number.

13004152531 is a deficient number, since it is larger than the sum of its proper divisors (1558901).

13004152531 is an equidigital number, since it uses as much as digits as its factorization.

13004152531 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1558900.

The product of its (nonzero) digits is 1800, while the sum is 25.

Adding to 13004152531 its reverse (13525140031), we get a palindrome (26529292562).

The spelling of 13004152531 in words is "thirteen billion, four million, one hundred fifty-two thousand, five hundred thirty-one".