Search a number
-
+
130042125523 is a prime number
BaseRepresentation
bin111100100011100011…
…1010101110011010011
3110102122212012102222101
41321013013111303103
54112311241004043
6135423542021231
712252364554202
oct1710707256323
9412585172871
10130042125523
1150172431712
1221252a17817
13c35583398b
146418d13239
1535b18d524d
hex1e471d5cd3

130042125523 has 2 divisors, whose sum is σ = 130042125524. Its totient is φ = 130042125522.

The previous prime is 130042125509. The next prime is 130042125527. The reversal of 130042125523 is 325521240031.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 130042125523 - 25 = 130042125491 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 130042125491 and 130042125500.

It is not a weakly prime, because it can be changed into another prime (130042125527) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65021062761 + 65021062762.

It is an arithmetic number, because the mean of its divisors is an integer number (65021062762).

Almost surely, 2130042125523 is an apocalyptic number.

130042125523 is a deficient number, since it is larger than the sum of its proper divisors (1).

130042125523 is an equidigital number, since it uses as much as digits as its factorization.

130042125523 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 7200, while the sum is 28.

Adding to 130042125523 its reverse (325521240031), we get a palindrome (455563365554).

The spelling of 130042125523 in words is "one hundred thirty billion, forty-two million, one hundred twenty-five thousand, five hundred twenty-three".