130042134441130 has 16 divisors (see below), whose sum is σ = 236896032862944. Its totient is φ = 51390144694480.

The previous prime is 130042134441077. The next prime is 130042134441151. The reversal of 130042134441130 is 31144431240031.

It is a junction number, because it is equal to n+sod(n) for n = 130042134441092 and 130042134441101.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 78338634376 + ... + 78338636035.

It is an arithmetic number, because the mean of its divisors is an integer number (14806002053934).

Almost surely, 2^{130042134441130} is an apocalyptic number.

130042134441130 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

130042134441130 is a deficient number, since it is larger than the sum of its proper divisors (106853898421814).

130042134441130 is a wasteful number, since it uses less digits than its factorization.

130042134441130 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 156677270501.

The product of its (nonzero) digits is 13824, while the sum is 31.

Adding to 130042134441130 its reverse (31144431240031), we get a palindrome (161186565681161).

The spelling of 130042134441130 in words is "one hundred thirty trillion, forty-two billion, one hundred thirty-four million, four hundred forty-one thousand, one hundred thirty".