1300423141411 has 4 divisors (see below), whose sum is σ = 1324959427152. Its totient is φ = 1275886855672.

The previous prime is 1300423141357. The next prime is 1300423141463. The reversal of 1300423141411 is 1141413240031.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1300423141411 - 2⁹ = 1300423140899 is a prime.

It is a super-2 number, since 2×1300423141411² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1300423141811) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 12268142791 + ... + 12268142896.

It is an arithmetic number, because the mean of its divisors is an integer number (331239856788).

Almost surely, 2^{1300423141411} is an apocalyptic number.

1300423141411 is a deficient number, since it is larger than the sum of its proper divisors (24536285741).

1300423141411 is an equidigital number, since it uses as much as digits as its factorization.

1300423141411 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 24536285740.

The product of its (nonzero) digits is 1152, while the sum is 25.

Adding to 1300423141411 its reverse (1141413240031), we get a palindrome (2441836381442).

The spelling of 1300423141411 in words is "one trillion, three hundred billion, four hundred twenty-three million, one hundred forty-one thousand, four hundred eleven".