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1300425000 = 2335572477
BaseRepresentation
bin100110110000010…
…1110100100101000
310100121222102201220
41031200232210220
510130402100000
6333012342040
744140300350
oct11540564450
93317872656
101300425000
11608068606
12303614920
13179556564
14c49d1b60
15792761a0
hex4d82e928

1300425000 has 192 divisors, whose sum is σ = 4645952640. Its totient is φ = 297120000.

The previous prime is 1300424987. The next prime is 1300425019. The reversal of 1300425000 is 5240031.

It is a super-2 number, since 2×13004250002 = 3382210361250000000, which contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (15).

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 523762 + ... + 526238.

It is an arithmetic number, because the mean of its divisors is an integer number (24197670).

Almost surely, 21300425000 is an apocalyptic number.

1300425000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 1300425000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (2322976320).

1300425000 is an abundant number, since it is smaller than the sum of its proper divisors (3345527640).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1300425000 is an equidigital number, since it uses as much as digits as its factorization.

1300425000 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2518 (or 2494 counting only the distinct ones).

The product of its (nonzero) digits is 120, while the sum is 15.

The square root of 1300425000 is about 36061.4059626077. The cubic root of 1300425000 is about 1091.5118039425.

Adding to 1300425000 its reverse (5240031), we get a palindrome (1305665031).

The spelling of 1300425000 in words is "one billion, three hundred million, four hundred twenty-five thousand".