13004300055 has 32 divisors (see below), whose sum is σ = 21934656000. Its totient is φ = 6560790912.

The previous prime is 13004300051. The next prime is 13004300063. The reversal of 13004300055 is 55000340031.

It is not a de Polignac number, because 13004300055 - 2² = 13004300051 is a prime.

It is a super-2 number, since 2×13004300055² (a number of 21 digits) contains 22 as substring.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13004300051) by changing a digit.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 159246 + ... + 226644.

It is an arithmetic number, because the mean of its divisors is an integer number (685458000).

Almost surely, 2^13004300055 is an apocalyptic number.

13004300055 is a gapful number since it is divisible by the number (15) formed by its first and last digit.

13004300055 is a deficient number, since it is larger than the sum of its proper divisors (8930355945).

13004300055 is a wasteful number, since it uses less digits than its factorization.

13004300055 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 68103.

The product of its (nonzero) digits is 900, while the sum is 21.

Adding to 13004300055 its reverse (55000340031), we get a palindrome (68004640086).

The spelling of 13004300055 in words is "thirteen billion, four million, three hundred thousand, fifty-five".