13004300144301 has 4 divisors (see below), whose sum is σ = 17339066859072. Its totient is φ = 8669533429532.

The previous prime is 13004300144257. The next prime is 13004300144401. The reversal of 13004300144301 is 10344100340031.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 13004300144301 - 2¹³ = 13004300136109 is a prime.

It is a super-2 number, since 2×13004300144301² (a number of 27 digits) contains 22 as substring.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13004300144401) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2167383357381 + ... + 2167383357386.

It is an arithmetic number, because the mean of its divisors is an integer number (4334766714768).

Almost surely, 2^{13004300144301} is an apocalyptic number.

It is an amenable number.

13004300144301 is a deficient number, since it is larger than the sum of its proper divisors (4334766714771).

13004300144301 is an equidigital number, since it uses as much as digits as its factorization.

13004300144301 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4334766714770.

The product of its (nonzero) digits is 1728, while the sum is 24.

Adding to 13004300144301 its reverse (10344100340031), we get a palindrome (23348400484332).

The spelling of 13004300144301 in words is "thirteen trillion, four billion, three hundred million, one hundred forty-four thousand, three hundred one".