Base | Representation |
---|---|
bin | 11000001110001110… |
… | …11110110000111111 |
3 | 1020120021220001122112 |
4 | 30013013132300333 |
5 | 203113100202143 |
6 | 5550223204235 |
7 | 640154520026 |
oct | 140707366077 |
9 | 36507801575 |
10 | 13004303423 |
11 | 5573654701 |
12 | 262b14667b |
13 | 12c324a6c7 |
14 | 8b51698bd |
15 | 511a01e18 |
hex | 3071dec3f |
13004303423 has 4 divisors (see below), whose sum is σ = 13306729128. Its totient is φ = 12701877720.
The previous prime is 13004303407. The next prime is 13004303443. The reversal of 13004303423 is 32430340031.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 13004303423 - 24 = 13004303407 is a prime.
It is a super-2 number, since 2×130043034232 (a number of 21 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13004303443) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 151212788 + ... + 151212873.
It is an arithmetic number, because the mean of its divisors is an integer number (3326682282).
Almost surely, 213004303423 is an apocalyptic number.
13004303423 is a deficient number, since it is larger than the sum of its proper divisors (302425705).
13004303423 is an equidigital number, since it uses as much as digits as its factorization.
13004303423 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 302425704.
The product of its (nonzero) digits is 2592, while the sum is 23.
Adding to 13004303423 its reverse (32430340031), we get a palindrome (45434643454).
The spelling of 13004303423 in words is "thirteen billion, four million, three hundred three thousand, four hundred twenty-three".
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