Base | Representation |
---|---|
bin | 11101100100011000000100… |
… | …111101111001011100101101 |
3 | 122001102222222110010211002212 |
4 | 131210120010331321130231 |
5 | 114021111233344420440 |
6 | 1140324550555300205 |
7 | 36251206216206014 |
oct | 3544300475713455 |
9 | 561388873124085 |
10 | 130043103123245 |
11 | 38487a74550734 |
12 | 1270328414a665 |
13 | 57740204b7240 |
14 | 2418196937a7b |
15 | 1007abd6e4465 |
hex | 764604f7972d |
130043103123245 has 32 divisors (see below), whose sum is σ = 168242376637440. Its totient is φ = 95925168069120.
The previous prime is 130043103123233. The next prime is 130043103123281. The reversal of 130043103123245 is 542321301340031.
It is a de Polignac number, because none of the positive numbers 2k-130043103123245 is a prime.
It is a super-2 number, since 2×1300431031232452 (a number of 29 digits) contains 22 as substring.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 2543306330 + ... + 2543357460.
It is an arithmetic number, because the mean of its divisors is an integer number (5257574269920).
Almost surely, 2130043103123245 is an apocalyptic number.
It is an amenable number.
130043103123245 is a deficient number, since it is larger than the sum of its proper divisors (38199273514195).
130043103123245 is a wasteful number, since it uses less digits than its factorization.
130043103123245 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 93845.
The product of its (nonzero) digits is 25920, while the sum is 32.
Adding to 130043103123245 its reverse (542321301340031), we get a palindrome (672364404463276).
The spelling of 130043103123245 in words is "one hundred thirty trillion, forty-three billion, one hundred three million, one hundred twenty-three thousand, two hundred forty-five".
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