Search a number
-
+
13004312561 is a prime number
BaseRepresentation
bin11000001110001111…
…00000111111110001
31020120021220112011222
430013013200333301
5203113101000221
65550223314425
7640154555462
oct140707407761
936507815158
1013004312561
115573660559
12262b14ba15
1312c3251906
148b516cd69
15511a049ab
hex3071e0ff1

13004312561 has 2 divisors, whose sum is σ = 13004312562. Its totient is φ = 13004312560.

The previous prime is 13004312551. The next prime is 13004312593. The reversal of 13004312561 is 16521340031.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 12852530161 + 151782400 = 113369^2 + 12320^2 .

It is a cyclic number.

It is not a de Polignac number, because 13004312561 - 230 = 11930570737 is a prime.

It is a super-2 number, since 2×130043125612 (a number of 21 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 13004312561.

It is not a weakly prime, because it can be changed into another prime (13004312521) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6502156280 + 6502156281.

It is an arithmetic number, because the mean of its divisors is an integer number (6502156281).

Almost surely, 213004312561 is an apocalyptic number.

It is an amenable number.

13004312561 is a deficient number, since it is larger than the sum of its proper divisors (1).

13004312561 is an equidigital number, since it uses as much as digits as its factorization.

13004312561 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2160, while the sum is 26.

Adding to 13004312561 its reverse (16521340031), we get a palindrome (29525652592).

The spelling of 13004312561 in words is "thirteen billion, four million, three hundred twelve thousand, five hundred sixty-one".