Base | Representation |
---|---|
bin | 11000001110001111… |
… | …00000111111110001 |
3 | 1020120021220112011222 |
4 | 30013013200333301 |
5 | 203113101000221 |
6 | 5550223314425 |
7 | 640154555462 |
oct | 140707407761 |
9 | 36507815158 |
10 | 13004312561 |
11 | 5573660559 |
12 | 262b14ba15 |
13 | 12c3251906 |
14 | 8b516cd69 |
15 | 511a049ab |
hex | 3071e0ff1 |
13004312561 has 2 divisors, whose sum is σ = 13004312562. Its totient is φ = 13004312560.
The previous prime is 13004312551. The next prime is 13004312593. The reversal of 13004312561 is 16521340031.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 12852530161 + 151782400 = 113369^2 + 12320^2 .
It is a cyclic number.
It is not a de Polignac number, because 13004312561 - 230 = 11930570737 is a prime.
It is a super-2 number, since 2×130043125612 (a number of 21 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 13004312561.
It is not a weakly prime, because it can be changed into another prime (13004312521) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6502156280 + 6502156281.
It is an arithmetic number, because the mean of its divisors is an integer number (6502156281).
Almost surely, 213004312561 is an apocalyptic number.
It is an amenable number.
13004312561 is a deficient number, since it is larger than the sum of its proper divisors (1).
13004312561 is an equidigital number, since it uses as much as digits as its factorization.
13004312561 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2160, while the sum is 26.
Adding to 13004312561 its reverse (16521340031), we get a palindrome (29525652592).
The spelling of 13004312561 in words is "thirteen billion, four million, three hundred twelve thousand, five hundred sixty-one".
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