Base | Representation |
---|---|
bin | 1011110100111100110111… |
… | …1000110001000111001011 |
3 | 1201001012102102202012210221 |
4 | 2331033031320301013023 |
5 | 3201030321433343444 |
6 | 43354034025450511 |
7 | 2511350115002014 |
oct | 275171570610713 |
9 | 51035372665727 |
10 | 13004320215499 |
11 | 4164112815628 |
12 | 15603a8640a37 |
13 | 7343c0a35152 |
14 | 32d5abad200b |
15 | 178413ab0a84 |
hex | bd3cde311cb |
13004320215499 has 2 divisors, whose sum is σ = 13004320215500. Its totient is φ = 13004320215498.
The previous prime is 13004320215461. The next prime is 13004320215541. The reversal of 13004320215499 is 99451202340031.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13004320215499 is a prime.
It is a super-2 number, since 2×130043202154992 (a number of 27 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (13004320515499) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6502160107749 + 6502160107750.
It is an arithmetic number, because the mean of its divisors is an integer number (6502160107750).
Almost surely, 213004320215499 is an apocalyptic number.
13004320215499 is a deficient number, since it is larger than the sum of its proper divisors (1).
13004320215499 is an equidigital number, since it uses as much as digits as its factorization.
13004320215499 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 233280, while the sum is 43.
The spelling of 13004320215499 in words is "thirteen trillion, four billion, three hundred twenty million, two hundred fifteen thousand, four hundred ninety-nine".
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