1300434001 has 2 divisors, whose sum is σ = 1300434002. Its totient is φ = 1300434000.

The previous prime is 1300433969. The next prime is 1300434011. The reversal of 1300434001 is 1004340031.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1267360000 + 33074001 = 35600^2 + 5751^2 .

It is an emirp because it is prime and its reverse (1004340031) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1300434001 - 2⁵ = 1300433969 is a prime.

It is a super-2 number, since 2×1300434001² = 3382257181913736002, which contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (1300434011) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 650217000 + 650217001.

It is an arithmetic number, because the mean of its divisors is an integer number (650217001).

Almost surely, 2^1300434001 is an apocalyptic number.

It is an amenable number.

1300434001 is a deficient number, since it is larger than the sum of its proper divisors (1).

1300434001 is an equidigital number, since it uses as much as digits as its factorization.

1300434001 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 144, while the sum is 16.

The square root of 1300434001 is about 36061.5307634049. The cubic root of 1300434001 is about 1091.5143222667.

Adding to 1300434001 its reverse (1004340031), we get a palindrome (2304774032).

The spelling of 1300434001 in words is "one billion, three hundred million, four hundred thirty-four thousand, one".