13004340210401 has 16 divisors (see below), whose sum is σ = 13530380071680. Its totient is φ = 12489464651520.

The previous prime is 13004340210373. The next prime is 13004340210431. The reversal of 13004340210401 is 10401204340031.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-13004340210401 is a prime.

It is a super-3 number, since 3×13004340210401³ (a number of 40 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13004340210431) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 2665160 + ... + 5754281.

It is an arithmetic number, because the mean of its divisors is an integer number (845648754480).

Almost surely, 2^{13004340210401} is an apocalyptic number.

It is an amenable number.

13004340210401 is a deficient number, since it is larger than the sum of its proper divisors (526039861279).

13004340210401 is an equidigital number, since it uses as much as digits as its factorization.

13004340210401 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 8420104.

The product of its (nonzero) digits is 1152, while the sum is 23.

Adding to 13004340210401 its reverse (10401204340031), we get a palindrome (23405544550432).

The spelling of 13004340210401 in words is "thirteen trillion, four billion, three hundred forty million, two hundred ten thousand, four hundred one".