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13004340210400 = 2552711235789567
BaseRepresentation
bin1011110100111100111100…
…0101000010101011100000
31201001012110211101001122211
42331033033011002223200
53201030342043213100
643354040022211504
72511350446650130
oct275171705025340
951035424331584
1013004340210400
114164123032040
1215603b3283b94
137343c4c16156
1432d5b0618ac0
151784157101ba
hexbd3cf142ae0

13004340210400 has 288 divisors, whose sum is σ = 39597717583872. Its totient is φ = 4051535923200.

The previous prime is 13004340210373. The next prime is 13004340210431. The reversal of 13004340210400 is 401204340031.

13004340210400 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a super-2 number, since 2×130043402104002 (a number of 27 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (22).

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 145146417 + ... + 145235983.

It is an arithmetic number, because the mean of its divisors is an integer number (137492074944).

Almost surely, 213004340210400 is an apocalyptic number.

13004340210400 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 13004340210400, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (19798858791936).

13004340210400 is an abundant number, since it is smaller than the sum of its proper divisors (26593377373472).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13004340210400 is a wasteful number, since it uses less digits than its factorization.

13004340210400 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 91962 (or 91949 counting only the distinct ones).

The product of its (nonzero) digits is 1152, while the sum is 22.

Adding to 13004340210400 its reverse (401204340031), we get a palindrome (13405544550431).

The spelling of 13004340210400 in words is "thirteen trillion, four billion, three hundred forty million, two hundred ten thousand, four hundred".