130044000000 has 252 divisors, whose sum is σ = 432667743032. Its totient is φ = 34675200000.

The previous prime is 130043999989. The next prime is 130044000017. The reversal of 130044000000 is 440031.

It is a super-2 number, since 2×130044000000² (a number of 23 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (12).

It is a self number, because there is not a number n which added to its sum of digits gives 130044000000.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 27 ways as a sum of consecutive naturals, for example, 11994582 + ... + 12005418.

Almost surely, 2^130044000000 is an apocalyptic number.

130044000000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 130044000000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (216333871516).

130044000000 is an abundant number, since it is smaller than the sum of its proper divisors (302623743032).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

130044000000 is an frugal number, since it uses more digits than its factorization.

130044000000 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 10886 (or 10847 counting only the distinct ones).

The product of its (nonzero) digits is 48, while the sum is 12.

Adding to 130044000000 its reverse (440031), we get a palindrome (130044440031).

The spelling of 130044000000 in words is "one hundred thirty billion, forty-four million", and thus it is an aban number.