130044000132 has 36 divisors (see below), whose sum is σ = 328852956796. Its totient is φ = 43330775040.

The previous prime is 130044000131. The next prime is 130044000221. The reversal of 130044000132 is 231000440031.

130044000132 is a `hidden beast` number, since 130 + 0 + 4 + 400 + 0 + 132 = 666.

130044000132 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It can be written as a sum of positive squares in 2 ways, for example, as 1581971076 + 128462029056 = 39774^2 + 358416^2 .

It is a tau number, because it is divible by the number of its divisors (36).

It is a super-2 number, since 2×130044000132² (a number of 23 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (18).

It is not an unprimeable number, because it can be changed into a prime (130044000131) by changing a digit.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 625693 + ... + 807204.

Almost surely, 2^130044000132 is an apocalyptic number.

130044000132 is a gapful number since it is divisible by the number (12) formed by its first and last digit.

It is an amenable number.

130044000132 is an abundant number, since it is smaller than the sum of its proper divisors (198808956664).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

130044000132 is a wasteful number, since it uses less digits than its factorization.

130044000132 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1435428 (or 1435423 counting only the distinct ones).

The product of its (nonzero) digits is 288, while the sum is 18.

Adding to 130044000132 its reverse (231000440031), we get a palindrome (361044440163).

The spelling of 130044000132 in words is "one hundred thirty billion, forty-four million, one hundred thirty-two", and thus it is an aban number.