1300440103 has 4 divisors (see below), whose sum is σ = 1313846800. Its totient is φ = 1287033408.

The previous prime is 1300440101. The next prime is 1300440107. The reversal of 1300440103 is 3010440031.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 3010440031 = 23 ⋅130888697.

It is a cyclic number.

It is not a de Polignac number, because 1300440103 - 2¹ = 1300440101 is a prime.

It is a super-2 number, since 2×1300440103² = 3382288922981301218, which contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1300440101) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6703203 + ... + 6703396.

It is an arithmetic number, because the mean of its divisors is an integer number (328461700).

Almost surely, 2^1300440103 is an apocalyptic number.

1300440103 is a deficient number, since it is larger than the sum of its proper divisors (13406697).

1300440103 is an equidigital number, since it uses as much as digits as its factorization.

1300440103 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 13406696.

The product of its (nonzero) digits is 144, while the sum is 16.

The square root of 1300440103 is about 36061.6153686992. The cubic root of 1300440103 is about 1091.5160294942.

Adding to 1300440103 its reverse (3010440031), we get a palindrome (4310880134).

The spelling of 1300440103 in words is "one billion, three hundred million, four hundred forty thousand, one hundred three".