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13004410022 = 26502205011
BaseRepresentation
bin11000001110001111…
…11000110010100110
31020120022002110212122
430013013320302212
5203113112110042
65550225345542
7640155442562
oct140707706246
936508073778
1013004410022
1155737177aa
12262b1982b2
1312c3287096
148b51966a2
15511a237d2
hex3071f8ca6

13004410022 has 4 divisors (see below), whose sum is σ = 19506615036. Its totient is φ = 6502205010.

The previous prime is 13004410021. The next prime is 13004410033. The reversal of 13004410022 is 22001440031.

13004410022 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It is a super-2 number, since 2×130044100222 (a number of 21 digits) contains 22 as substring.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13004410021) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3251102504 + ... + 3251102507.

It is an arithmetic number, because the mean of its divisors is an integer number (4876653759).

Almost surely, 213004410022 is an apocalyptic number.

13004410022 is a deficient number, since it is larger than the sum of its proper divisors (6502205014).

13004410022 is an equidigital number, since it uses as much as digits as its factorization.

13004410022 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 6502205013.

The product of its (nonzero) digits is 192, while the sum is 17.

Adding to 13004410022 its reverse (22001440031), we get a palindrome (35005850053).

The spelling of 13004410022 in words is "thirteen billion, four million, four hundred ten thousand, twenty-two".

Divisors: 1 2 6502205011 13004410022