Base | Representation |
---|---|
bin | 11000001110001111… |
… | …11101101110101011 |
3 | 1020120022010111121212 |
4 | 30013013331232223 |
5 | 203113113232001 |
6 | 5550230023335 |
7 | 640155555551 |
oct | 140707755653 |
9 | 36508114555 |
10 | 13004430251 |
11 | 5573730a1a |
12 | 262b1a7b4b |
13 | 12c3293357 |
14 | 8b519dbd1 |
15 | 511a297bb |
hex | 3071fdbab |
13004430251 has 2 divisors, whose sum is σ = 13004430252. Its totient is φ = 13004430250.
The previous prime is 13004430233. The next prime is 13004430287. The reversal of 13004430251 is 15203440031.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13004430251 is a prime.
It is not a weakly prime, because it can be changed into another prime (13004430221) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6502215125 + 6502215126.
It is an arithmetic number, because the mean of its divisors is an integer number (6502215126).
Almost surely, 213004430251 is an apocalyptic number.
13004430251 is a deficient number, since it is larger than the sum of its proper divisors (1).
13004430251 is an equidigital number, since it uses as much as digits as its factorization.
13004430251 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1440, while the sum is 23.
Adding to 13004430251 its reverse (15203440031), we get a palindrome (28207870282).
The spelling of 13004430251 in words is "thirteen billion, four million, four hundred thirty thousand, two hundred fifty-one".
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