Base | Representation |
---|---|
bin | 1011110100111101010100… |
… | …0001101111110111110011 |
3 | 1201001012201210011102021201 |
4 | 2331033111001233313303 |
5 | 3201031043120311402 |
6 | 43354053545232031 |
7 | 2511353101146541 |
oct | 275172501576763 |
9 | 51035653142251 |
10 | 13004440010227 |
11 | 41641743a7136 |
12 | 1560420792617 |
13 | 73440c7b97c3 |
14 | 32d5bd996d91 |
15 | 17841e375687 |
hex | bd3d506fdf3 |
13004440010227 has 2 divisors, whose sum is σ = 13004440010228. Its totient is φ = 13004440010226.
The previous prime is 13004440010171. The next prime is 13004440010281. The reversal of 13004440010227 is 72201004440031.
It is a strong prime.
It is an emirp because it is prime and its reverse (72201004440031) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13004440010227 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 13004440010195 and 13004440010204.
It is not a weakly prime, because it can be changed into another prime (13004440070227) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6502220005113 + 6502220005114.
It is an arithmetic number, because the mean of its divisors is an integer number (6502220005114).
Almost surely, 213004440010227 is an apocalyptic number.
13004440010227 is a deficient number, since it is larger than the sum of its proper divisors (1).
13004440010227 is an equidigital number, since it uses as much as digits as its factorization.
13004440010227 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 5376, while the sum is 28.
Adding to 13004440010227 its reverse (72201004440031), we get a palindrome (85205444450258).
The spelling of 13004440010227 in words is "thirteen trillion, four billion, four hundred forty million, ten thousand, two hundred twenty-seven".
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