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13004440010227 is a prime number
BaseRepresentation
bin1011110100111101010100…
…0001101111110111110011
31201001012201210011102021201
42331033111001233313303
53201031043120311402
643354053545232031
72511353101146541
oct275172501576763
951035653142251
1013004440010227
1141641743a7136
121560420792617
1373440c7b97c3
1432d5bd996d91
1517841e375687
hexbd3d506fdf3

13004440010227 has 2 divisors, whose sum is σ = 13004440010228. Its totient is φ = 13004440010226.

The previous prime is 13004440010171. The next prime is 13004440010281. The reversal of 13004440010227 is 72201004440031.

It is a strong prime.

It is an emirp because it is prime and its reverse (72201004440031) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13004440010227 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 13004440010195 and 13004440010204.

It is not a weakly prime, because it can be changed into another prime (13004440070227) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6502220005113 + 6502220005114.

It is an arithmetic number, because the mean of its divisors is an integer number (6502220005114).

Almost surely, 213004440010227 is an apocalyptic number.

13004440010227 is a deficient number, since it is larger than the sum of its proper divisors (1).

13004440010227 is an equidigital number, since it uses as much as digits as its factorization.

13004440010227 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 5376, while the sum is 28.

Adding to 13004440010227 its reverse (72201004440031), we get a palindrome (85205444450258).

The spelling of 13004440010227 in words is "thirteen trillion, four billion, four hundred forty million, ten thousand, two hundred twenty-seven".