Base | Representation |
---|---|
bin | 11000001110010000… |
… | …00000110000110010 |
3 | 1020120022011010122222 |
4 | 30013020000300302 |
5 | 203113114131144 |
6 | 5550230201042 |
7 | 640155640016 |
oct | 140710006062 |
9 | 36508133588 |
10 | 13004442674 |
11 | 557373a293 |
12 | 262b1b3182 |
13 | 12c3298bc2 |
14 | 8b51a4546 |
15 | 511a2d2ee |
hex | 307200c32 |
13004442674 has 4 divisors (see below), whose sum is σ = 19506664014. Its totient is φ = 6502221336.
The previous prime is 13004442667. The next prime is 13004442677. The reversal of 13004442674 is 47624440031.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 9720579649 + 3283863025 = 98593^2 + 57305^2 .
It is a super-2 number, since 2×130044426742 (a number of 21 digits) contains 22 as substring.
It is a Curzon number.
It is not an unprimeable number, because it can be changed into a prime (13004442677) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (11) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3251110667 + ... + 3251110670.
Almost surely, 213004442674 is an apocalyptic number.
13004442674 is a deficient number, since it is larger than the sum of its proper divisors (6502221340).
13004442674 is an equidigital number, since it uses as much as digits as its factorization.
13004442674 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 6502221339.
The product of its (nonzero) digits is 64512, while the sum is 35.
The spelling of 13004442674 in words is "thirteen billion, four million, four hundred forty-two thousand, six hundred seventy-four".
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