Base | Representation |
---|---|
bin | 11000001110010000… |
… | …00000110000110101 |
3 | 1020120022011010200002 |
4 | 30013020000300311 |
5 | 203113114131202 |
6 | 5550230201045 |
7 | 640155640022 |
oct | 140710006065 |
9 | 36508133602 |
10 | 13004442677 |
11 | 557373a296 |
12 | 262b1b3185 |
13 | 12c3298bc5 |
14 | 8b51a4549 |
15 | 511a2d302 |
hex | 307200c35 |
13004442677 has 2 divisors, whose sum is σ = 13004442678. Its totient is φ = 13004442676.
The previous prime is 13004442667. The next prime is 13004442709. The reversal of 13004442677 is 77624440031.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 9585584836 + 3418857841 = 97906^2 + 58471^2 .
It is an emirp because it is prime and its reverse (77624440031) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 13004442677 - 226 = 12937333813 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 13004442677.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13004442667) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6502221338 + 6502221339.
It is an arithmetic number, because the mean of its divisors is an integer number (6502221339).
Almost surely, 213004442677 is an apocalyptic number.
It is an amenable number.
13004442677 is a deficient number, since it is larger than the sum of its proper divisors (1).
13004442677 is an equidigital number, since it uses as much as digits as its factorization.
13004442677 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 112896, while the sum is 38.
The spelling of 13004442677 in words is "thirteen billion, four million, four hundred forty-two thousand, six hundred seventy-seven".
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