Base | Representation |
---|---|
bin | 11000001110010001… |
… | …01101001001101001 |
3 | 1020120022111101001212 |
4 | 30013020231021221 |
5 | 203113140440424 |
6 | 5550234122505 |
7 | 640160325053 |
oct | 140710551151 |
9 | 36508441055 |
10 | 13004624489 |
11 | 557385394a |
12 | 262b280435 |
13 | 12c333089c |
14 | 8b52108d3 |
15 | 511a6710e |
hex | 30722d269 |
13004624489 has 2 divisors, whose sum is σ = 13004624490. Its totient is φ = 13004624488.
The previous prime is 13004624459. The next prime is 13004624513. The reversal of 13004624489 is 98442640031.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 9557995225 + 3446629264 = 97765^2 + 58708^2 .
It is a cyclic number.
It is not a de Polignac number, because 13004624489 - 224 = 12987847273 is a prime.
It is a super-2 number, since 2×130046244892 (a number of 21 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (13004624459) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6502312244 + 6502312245.
It is an arithmetic number, because the mean of its divisors is an integer number (6502312245).
Almost surely, 213004624489 is an apocalyptic number.
It is an amenable number.
13004624489 is a deficient number, since it is larger than the sum of its proper divisors (1).
13004624489 is an equidigital number, since it uses as much as digits as its factorization.
13004624489 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 165888, while the sum is 41.
The spelling of 13004624489 in words is "thirteen billion, four million, six hundred twenty-four thousand, four hundred eighty-nine".
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