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130049712000 = 273553133183
BaseRepresentation
bin111100100011110010…
…0010001111110000000
3110102200101110212200000
41321013210101332000
54112320211241000
6135424412400000
712252516212205
oct1710744217600
9412611425600
10130049712000
115017674352a
1221255476000
13c35728bb10
146419d29cac
1535b23d3000
hex1e47911f80

130049712000 has 1536 divisors, whose sum is σ = 544908349440. Its totient is φ = 30606336000.

The previous prime is 130049711999. The next prime is 130049712017. The reversal of 130049712000 is 217940031.

It is a Harshad number since it is a multiple of its sum of digits (27).

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 191 ways as a sum of consecutive naturals, for example, 1566863959 + ... + 1566864041.

It is an arithmetic number, because the mean of its divisors is an integer number (354758040).

Almost surely, 2130049712000 is an apocalyptic number.

130049712000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 130049712000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (272454174720).

130049712000 is an abundant number, since it is smaller than the sum of its proper divisors (414858637440).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

130049712000 is an equidigital number, since it uses as much as digits as its factorization.

130049712000 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 171 (or 137 counting only the distinct ones).

The product of its (nonzero) digits is 1512, while the sum is 27.

The spelling of 130049712000 in words is "one hundred thirty billion, forty-nine million, seven hundred twelve thousand".