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13005045542 = 26502522771
BaseRepresentation
bin11000001110010100…
…10011111100100110
31020120100021202122102
430013022103330212
5203113242424132
65550251132102
7640164030446
oct140712237446
936510252572
1013005045542
115574011225
12262b444032
1312c344a428
148b52c0126
15511aebc62
hex307293f26

13005045542 has 4 divisors (see below), whose sum is σ = 19507568316. Its totient is φ = 6502522770.

The previous prime is 13005045541. The next prime is 13005045551. The reversal of 13005045542 is 24554050031.

13005045542 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 24554050031 = 73507721433.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13005045541) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3251261384 + ... + 3251261387.

It is an arithmetic number, because the mean of its divisors is an integer number (4876892079).

Almost surely, 213005045542 is an apocalyptic number.

13005045542 is a deficient number, since it is larger than the sum of its proper divisors (6502522774).

13005045542 is an equidigital number, since it uses as much as digits as its factorization.

13005045542 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 6502522773.

The product of its (nonzero) digits is 12000, while the sum is 29.

Adding to 13005045542 its reverse (24554050031), we get a palindrome (37559095573).

The spelling of 13005045542 in words is "thirteen billion, five million, forty-five thousand, five hundred forty-two".

Divisors: 1 2 6502522771 13005045542