Base | Representation |
---|---|
bin | 11000001110010100… |
… | …11010100011000100 |
3 | 1020120100100010201211 |
4 | 30013022122203010 |
5 | 203113244310310 |
6 | 5550251501204 |
7 | 640164202333 |
oct | 140712324304 |
9 | 36510303654 |
10 | 13005072580 |
11 | 557402a575 |
12 | 262b457804 |
13 | 12c3459826 |
14 | 8b52c9d1a |
15 | 511b04c8a |
hex | 30729a8c4 |
13005072580 has 12 divisors (see below), whose sum is σ = 27310652460. Its totient is φ = 5202029024.
The previous prime is 13005072517. The next prime is 13005072617. The reversal of 13005072580 is 8527050031.
It can be written as a sum of positive squares in 2 ways, for example, as 10270200964 + 2734871616 = 101342^2 + 52296^2 .
It is a super-2 number, since 2×130050725802 (a number of 21 digits) contains 22 as substring.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 325126795 + ... + 325126834.
It is an arithmetic number, because the mean of its divisors is an integer number (2275887705).
Almost surely, 213005072580 is an apocalyptic number.
13005072580 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
13005072580 is an abundant number, since it is smaller than the sum of its proper divisors (14305579880).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13005072580 is a wasteful number, since it uses less digits than its factorization.
13005072580 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 650253638 (or 650253636 counting only the distinct ones).
The product of its (nonzero) digits is 8400, while the sum is 31.
The spelling of 13005072580 in words is "thirteen billion, five million, seventy-two thousand, five hundred eighty".
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