Base | Representation |
---|---|
bin | 10010111011001100100… |
… | …101101001011000111010 |
3 | 11121022211221210101211220 |
4 | 102323030211221120322 |
5 | 132301422202404224 |
6 | 2433240333132510 |
7 | 162646625142564 |
oct | 22731445513072 |
9 | 4538757711756 |
10 | 1300512544314 |
11 | 4615a9477335 |
12 | 19006b02a136 |
13 | 9583a3521b9 |
14 | 46d33688334 |
15 | 23c68e1a279 |
hex | 12ecc96963a |
1300512544314 has 32 divisors (see below), whose sum is σ = 2688909410880. Its totient is φ = 419050800000.
The previous prime is 1300512544307. The next prime is 1300512544343. The reversal of 1300512544314 is 4134452150031.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 24223812 + ... + 24277439.
It is an arithmetic number, because the mean of its divisors is an integer number (84028419090).
Almost surely, 21300512544314 is an apocalyptic number.
1300512544314 is an abundant number, since it is smaller than the sum of its proper divisors (1388396866566).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1300512544314 is a wasteful number, since it uses less digits than its factorization.
1300512544314 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 48501406.
The product of its (nonzero) digits is 28800, while the sum is 33.
Adding to 1300512544314 its reverse (4134452150031), we get a palindrome (5434964694345).
The spelling of 1300512544314 in words is "one trillion, three hundred billion, five hundred twelve million, five hundred forty-four thousand, three hundred fourteen".
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