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13005211212000 = 2532537241214141
BaseRepresentation
bin1011110101000000001011…
…1111101001100011100000
31201001021201112022112020100
42331100002333221203200
53201034133032241000
643354302254542400
72511411154231320
oct275200277514340
951037645275210
1013005211212000
11416452a758477
1215605b6b07a00
137345034c8707
1432d654187280
15178466e0ea00
hexbd402fe98e0

13005211212000 has 576 divisors, whose sum is σ = 52968260112768. Its totient is φ = 2960271360000.

The previous prime is 13005211211963. The next prime is 13005211212001. The reversal of 13005211212000 is 21211250031.

13005211212000 is a `hidden beast` number, since 1 + 3 + 0 + 0 + 521 + 121 + 20 + 0 + 0 = 666.

It is a Harshad number since it is a multiple of its sum of digits (18).

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13005211212001) by changing a digit.

It is a polite number, since it can be written in 95 ways as a sum of consecutive naturals, for example, 60624930 + ... + 60839070.

It is an arithmetic number, because the mean of its divisors is an integer number (91958784918).

Almost surely, 213005211212000 is an apocalyptic number.

13005211212000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 13005211212000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (26484130056384).

13005211212000 is an abundant number, since it is smaller than the sum of its proper divisors (39963048900768).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13005211212000 is a wasteful number, since it uses less digits than its factorization.

13005211212000 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 214420 (or 214399 counting only the distinct ones).

The product of its (nonzero) digits is 120, while the sum is 18.

Adding to 13005211212000 its reverse (21211250031), we get a palindrome (13026422462031).

The spelling of 13005211212000 in words is "thirteen trillion, five billion, two hundred eleven million, two hundred twelve thousand".