Base | Representation |
---|---|
bin | 1011110101000000001111… |
… | …0100110011010010111111 |
3 | 1201001021202111112102110012 |
4 | 2331100003310303102333 |
5 | 3201034200114124120 |
6 | 43354303513333435 |
7 | 2511411413533010 |
oct | 275200364632277 |
9 | 51037674472405 |
10 | 13005225145535 |
11 | 4164537604997 |
12 | 15605bb70727b |
13 | 7345063667cc |
14 | 32d655d73007 |
15 | 1784682631c5 |
hex | bd403d334bf |
13005225145535 has 32 divisors (see below), whose sum is σ = 19705980920832. Its totient is φ = 8028362580480.
The previous prime is 13005225145519. The next prime is 13005225145571. The reversal of 13005225145535 is 53554152250031.
It is not a de Polignac number, because 13005225145535 - 24 = 13005225145519 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 13005225145492 and 13005225145501.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 475149821 + ... + 475177190.
It is an arithmetic number, because the mean of its divisors is an integer number (615811903776).
Almost surely, 213005225145535 is an apocalyptic number.
13005225145535 is a deficient number, since it is larger than the sum of its proper divisors (6700755775297).
13005225145535 is a wasteful number, since it uses less digits than its factorization.
13005225145535 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 950327063.
The product of its (nonzero) digits is 450000, while the sum is 41.
Adding to 13005225145535 its reverse (53554152250031), we get a palindrome (66559377395566).
The spelling of 13005225145535 in words is "thirteen trillion, five billion, two hundred twenty-five million, one hundred forty-five thousand, five hundred thirty-five".
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