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13005225410405 = 52601045082081
BaseRepresentation
bin1011110101000000001111…
…0101110011111101100101
31201001021202112000212210012
42331100003311303331211
53201034200201113110
643354303523140005
72511411416015144
oct275200365637545
951037675025705
1013005225410405
114164537775998
1215605bb814605
1373450642a237
1432d65600175b
151784682b6905
hexbd403d73f65

13005225410405 has 4 divisors (see below), whose sum is σ = 15606270492492. Its totient is φ = 10404180328320.

The previous prime is 13005225410377. The next prime is 13005225410477. The reversal of 13005225410405 is 50401452250031.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 6431057618209 + 6574167792196 = 2535953^2 + 2564014^2 .

It is not a de Polignac number, because 13005225410405 - 216 = 13005225344869 is a prime.

It is a Duffinian number.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1300522541036 + ... + 1300522541045.

It is an arithmetic number, because the mean of its divisors is an integer number (3901567623123).

Almost surely, 213005225410405 is an apocalyptic number.

It is an amenable number.

13005225410405 is a deficient number, since it is larger than the sum of its proper divisors (2601045082087).

13005225410405 is an equidigital number, since it uses as much as digits as its factorization.

13005225410405 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2601045082086.

The product of its (nonzero) digits is 24000, while the sum is 32.

Adding to 13005225410405 its reverse (50401452250031), we get a palindrome (63406677660436).

The spelling of 13005225410405 in words is "thirteen trillion, five billion, two hundred twenty-five million, four hundred ten thousand, four hundred five".

Divisors: 1 5 2601045082081 13005225410405