Base | Representation |
---|---|
bin | 1011110101000000001111… |
… | …0101110011111101100101 |
3 | 1201001021202112000212210012 |
4 | 2331100003311303331211 |
5 | 3201034200201113110 |
6 | 43354303523140005 |
7 | 2511411416015144 |
oct | 275200365637545 |
9 | 51037675025705 |
10 | 13005225410405 |
11 | 4164537775998 |
12 | 15605bb814605 |
13 | 73450642a237 |
14 | 32d65600175b |
15 | 1784682b6905 |
hex | bd403d73f65 |
13005225410405 has 4 divisors (see below), whose sum is σ = 15606270492492. Its totient is φ = 10404180328320.
The previous prime is 13005225410377. The next prime is 13005225410477. The reversal of 13005225410405 is 50401452250031.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 6431057618209 + 6574167792196 = 2535953^2 + 2564014^2 .
It is not a de Polignac number, because 13005225410405 - 216 = 13005225344869 is a prime.
It is a Duffinian number.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1300522541036 + ... + 1300522541045.
It is an arithmetic number, because the mean of its divisors is an integer number (3901567623123).
Almost surely, 213005225410405 is an apocalyptic number.
It is an amenable number.
13005225410405 is a deficient number, since it is larger than the sum of its proper divisors (2601045082087).
13005225410405 is an equidigital number, since it uses as much as digits as its factorization.
13005225410405 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2601045082086.
The product of its (nonzero) digits is 24000, while the sum is 32.
Adding to 13005225410405 its reverse (50401452250031), we get a palindrome (63406677660436).
The spelling of 13005225410405 in words is "thirteen trillion, five billion, two hundred twenty-five million, four hundred ten thousand, four hundred five".
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