Base | Representation |
---|---|
bin | 111100100011110111… |
… | …1000100110001010011 |
3 | 110102200120210122001011 |
4 | 1321013233010301103 |
5 | 4112321422312043 |
6 | 135424553151351 |
7 | 12252552235432 |
oct | 1710757046123 |
9 | 412616718034 |
10 | 130052541523 |
11 | 501782a6383 |
12 | 212563bb557 |
13 | c357a3c9a8 |
14 | 641a465119 |
15 | 35b279159d |
hex | 1e47bc4c53 |
130052541523 has 2 divisors, whose sum is σ = 130052541524. Its totient is φ = 130052541522.
The previous prime is 130052541481. The next prime is 130052541529. The reversal of 130052541523 is 325145250031.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 130052541523 - 229 = 129515670611 is a prime.
It is not a weakly prime, because it can be changed into another prime (130052541529) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65026270761 + 65026270762.
It is an arithmetic number, because the mean of its divisors is an integer number (65026270762).
Almost surely, 2130052541523 is an apocalyptic number.
130052541523 is a deficient number, since it is larger than the sum of its proper divisors (1).
130052541523 is an equidigital number, since it uses as much as digits as its factorization.
130052541523 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 18000, while the sum is 31.
Adding to 130052541523 its reverse (325145250031), we get a palindrome (455197791554).
The spelling of 130052541523 in words is "one hundred thirty billion, fifty-two million, five hundred forty-one thousand, five hundred twenty-three".
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