Base | Representation |
---|---|
bin | 10010111011001101101… |
… | …010100010100100011001 |
3 | 11121022220012202221111202 |
4 | 102323031222202210121 |
5 | 132301441313314223 |
6 | 2433242220203545 |
7 | 162650234511623 |
oct | 22731552424431 |
9 | 4538805687452 |
10 | 1300530604313 |
11 | 461608692056 |
12 | 1900750995b5 |
13 | 958410065a5 |
14 | 46d35c29c13 |
15 | 23c6a7d6428 |
hex | 12ecdaa2919 |
1300530604313 has 2 divisors, whose sum is σ = 1300530604314. Its totient is φ = 1300530604312.
The previous prime is 1300530604297. The next prime is 1300530604333. The reversal of 1300530604313 is 3134060350031.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1295141869849 + 5388734464 = 1138043^2 + 73408^2 .
It is a cyclic number.
It is not a de Polignac number, because 1300530604313 - 24 = 1300530604297 is a prime.
It is not a weakly prime, because it can be changed into another prime (1300530604333) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 650265302156 + 650265302157.
It is an arithmetic number, because the mean of its divisors is an integer number (650265302157).
Almost surely, 21300530604313 is an apocalyptic number.
It is an amenable number.
1300530604313 is a deficient number, since it is larger than the sum of its proper divisors (1).
1300530604313 is an equidigital number, since it uses as much as digits as its factorization.
1300530604313 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 9720, while the sum is 29.
Adding to 1300530604313 its reverse (3134060350031), we get a palindrome (4434590954344).
The spelling of 1300530604313 in words is "one trillion, three hundred billion, five hundred thirty million, six hundred four thousand, three hundred thirteen".
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