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1300530604313 is a prime number
BaseRepresentation
bin10010111011001101101…
…010100010100100011001
311121022220012202221111202
4102323031222202210121
5132301441313314223
62433242220203545
7162650234511623
oct22731552424431
94538805687452
101300530604313
11461608692056
121900750995b5
13958410065a5
1446d35c29c13
1523c6a7d6428
hex12ecdaa2919

1300530604313 has 2 divisors, whose sum is σ = 1300530604314. Its totient is φ = 1300530604312.

The previous prime is 1300530604297. The next prime is 1300530604333. The reversal of 1300530604313 is 3134060350031.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1295141869849 + 5388734464 = 1138043^2 + 73408^2 .

It is a cyclic number.

It is not a de Polignac number, because 1300530604313 - 24 = 1300530604297 is a prime.

It is not a weakly prime, because it can be changed into another prime (1300530604333) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 650265302156 + 650265302157.

It is an arithmetic number, because the mean of its divisors is an integer number (650265302157).

Almost surely, 21300530604313 is an apocalyptic number.

It is an amenable number.

1300530604313 is a deficient number, since it is larger than the sum of its proper divisors (1).

1300530604313 is an equidigital number, since it uses as much as digits as its factorization.

1300530604313 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 9720, while the sum is 29.

Adding to 1300530604313 its reverse (3134060350031), we get a palindrome (4434590954344).

The spelling of 1300530604313 in words is "one trillion, three hundred billion, five hundred thirty million, six hundred four thousand, three hundred thirteen".