130053366416377 has 2 divisors, whose sum is σ = 130053366416378. Its totient is φ = 130053366416376.

The previous prime is 130053366416333. The next prime is 130053366416401. The reversal of 130053366416377 is 773614663350031.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 127676801941056 + 2376564475321 = 11299416^2 + 1541611^2 .

It is a cyclic number.

It is not a de Polignac number, because 130053366416377 - 2¹¹ = 130053366414329 is a prime.

It is a super-2 number, since 2×130053366416377² (a number of 29 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (130053366486377) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65026683208188 + 65026683208189.

It is an arithmetic number, because the mean of its divisors is an integer number (65026683208189).

Almost surely, 2^{130053366416377} is an apocalyptic number.

It is an amenable number.

130053366416377 is a deficient number, since it is larger than the sum of its proper divisors (1).

130053366416377 is an equidigital number, since it uses as much as digits as its factorization.

130053366416377 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 17146080, while the sum is 55.

The spelling of 130053366416377 in words is "one hundred thirty trillion, fifty-three billion, three hundred sixty-six million, four hundred sixteen thousand, three hundred seventy-seven".