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13005340215044 = 223251335053761
BaseRepresentation
bin1011110101000000101010…
…1011110000011100000100
31201001022001112001120010212
42331100022223300130010
53201034414043340134
643354323143534552
72511414311600432
oct275201253603404
951038045046125
1013005340215044
114164596559361
12156063215a458
13734524155488
1432d667367d52
151784733e2bce
hexbd40aaf0704

13005340215044 has 6 divisors (see below), whose sum is σ = 22759345376334. Its totient is φ = 6502670107520.

The previous prime is 13005340215013. The next prime is 13005340215059. The reversal of 13005340215044 is 44051204350031.

It can be written as a sum of positive squares in only one way, i.e., 12651181922500 + 354158292544 = 3556850^2 + 595112^2 .

It is a self number, because there is not a number n which added to its sum of digits gives 13005340215044.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1625667526877 + ... + 1625667526884.

It is an arithmetic number, because the mean of its divisors is an integer number (3793224229389).

Almost surely, 213005340215044 is an apocalyptic number.

It is an amenable number.

13005340215044 is a deficient number, since it is larger than the sum of its proper divisors (9754005161290).

13005340215044 is a wasteful number, since it uses less digits than its factorization.

13005340215044 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3251335053765 (or 3251335053763 counting only the distinct ones).

The product of its (nonzero) digits is 28800, while the sum is 32.

Adding to 13005340215044 its reverse (44051204350031), we get a palindrome (57056544565075).

The spelling of 13005340215044 in words is "thirteen trillion, five billion, three hundred forty million, two hundred fifteen thousand, forty-four".

Divisors: 1 2 4 3251335053761 6502670107522 13005340215044